c^2-12c+27=0

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Solution for c^2-12c+27=0 equation:


Simplifying
c2 + -12c + 27 = 0

Reorder the terms:
27 + -12c + c2 = 0

Solving
27 + -12c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + -1c)(9 + -1c) = 0

Subproblem 1

Set the factor '(3 + -1c)' equal to zero and attempt to solve: Simplifying 3 + -1c = 0 Solving 3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1c = 0 + -3 -1c = 0 + -3 Combine like terms: 0 + -3 = -3 -1c = -3 Divide each side by '-1'. c = 3 Simplifying c = 3

Subproblem 2

Set the factor '(9 + -1c)' equal to zero and attempt to solve: Simplifying 9 + -1c = 0 Solving 9 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1c = 0 + -9 -1c = 0 + -9 Combine like terms: 0 + -9 = -9 -1c = -9 Divide each side by '-1'. c = 9 Simplifying c = 9

Solution

c = {3, 9}

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